20x^2+96x-20=0

Solution for 20x^2+96x-20=0 equation:

20x^2+96x-20=0

a = 20; b = 96; c = -20;
Δ = b2-4ac
Δ = 962-4·20·(-20)
Δ = 10816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10816}=104$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-104}{2*20}=\frac{-200}{40}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+104}{2*20}=\frac{8}{40}
=1/5
$